For the circuit shown in the figure,the direction and magnitude of the force on the segment $PQR$ is:

  • A
    No resultant force acts on the loop
  • B
    $ILB$ out of the page
  • C
    $\frac{1}{2} ILB$ into the page
  • D
    $ILB$ into the page

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Similar Questions

As shown in the figure, a uniform straight wire of length $30 \sqrt{3} \text{ cm}$ is bent in the form of an equilateral triangle $ABC$. $A$ uniform magnetic field $2 \text{ T}$ is applied parallel to the side $BC$. If the current through the wire is $2 \text{ A}$, the magnitude of the force on the side $AC$ is ($\overline{B}$ represents the direction of the magnetic field).

$A$ long current-carrying conductor is placed near a rectangular current loop as shown in the figure. Calculate the resultant force on the current loop.

Find the force per unit length at point $P$. The current in the wire is $5 \, A$ and the distance between the parallel segments is $10 \, cm$.

The force exerted by a magnetic field on a wire having length $L$ and current $I$ is perpendicular to the wire and given as $|F| = IL|B|$. An experimental plot shows $|F|$ as a function of $L$. The plot is a straight line with a slope $S = (10 \pm 1) \times 10^{-5} \ T$. The current in the wire is $I = (15 \pm 1) \ mA$. The percentage error in $B$ is:

Three straight parallel current-carrying conductors are shown in the figure. The force experienced by the middle conductor of length $25\, cm$ is

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